disintegrates to give 
as the final product. How many alpha and beta particles are emitted during this process ? Express answer as number of α -particle + number of β -particle emitted.
Text Solution
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Since the change in mass number is only due to the emission of α -particle, we have
Number of α -particle emitted = 
= 7
Now the associated decrease in atomic number would be 14 (= 2 × 7) and thus the atomic number of the daughter atom would be 76 (= 90– 14). But the actual atomic number of lead is 82 e. the atomic number is six more than expected. This is because of the emission β -particle. Since there is an increase of one in atomic number due to the emission of one β -particle, we have
Number of β -particles emitted = 
= 6
Hence, number of α -particles emitted = 7
Number of β -particles emitted = 6.
Answer is 6 + 7 = 13.
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